prueba ley de coulomb - Fisica Basica

$f_k = f(x_k),\: x_k = x^*+kh,\: k=-\frac{N-1}{2},\dots,\frac{N-1}{2}$

$7gal(\frac{3.785l}{1gal})(\frac{1000cm^{3}}{1l})= 26495cm^{3}$

(1) $\begin{equation*} P_{N-1}(x)=\sum_{j=0}^{N-1}{a_jx^j} \end{equation*}$

(2) $\begin{equation*} \left\{ P_{N-1}(x_k) = f_k\right\},\quad k=-\frac{N-1}{2},\dots,\frac{N-1}{2} \end{equation*}$

$q2=\frac{(0.237N)x(3.5m)^{3}}{[9x10^{9}\frac{Nm^{2}}{C^{2}}]x-6x10^{-7}C}$

$q2=\frac{2.9Nm^{2}}{[9x10^{9}\frac{Nm^{2}}{C^{2}}]x-6x10^{-7}C}$

$q2=\frac{2.9Nm^{2}}{[-5400\frac{Nm^{2}}{C}]}$

$q2=-0.537x10^{-3}C}$

$F=[9x10^{9}\frac{Nm^{2}}{C^{2}}]x\frac{(-3x10^{-6}C)x(7x10^{-6}C)}{{(0.7m)^2}}=-0.3857N$

$d=\sqrt{\frac{(9x10^{9}\frac{Nm^{2}}{C^{2}})x(3.8x10^{-7}C)x(7.5x10^{-3}C)}{10N}}$

$d=\sqrt{\frac{0.256Nm^{2}}{10N}}=\sqrt{0.0256m^{2}}=0.16m$

$q2=\frac{(6x10^{-1})x(0.35m)^{2}}{[9x10^{9}\frac{Nm^{2}}{C^{2}}]x(5x10^{-6}C)}$

$q2=1.63x10^{-6}C$

$F1=8.99x10^{9}*\frac{(+1.6x10^{-19})x(-1.6x10^{-19})}{(30x10^{-6})^{2}}=-2.56x10^{-19}N$

$F2=8.99x10^{9}*\frac{(+1.6x10^{-19})x(-1.6x10^{-19})}{(20x10^{-6})^{2}}=-5.75x10^{-19}N$

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